#include <iostream> #include <cstdio> #include <cmath> #include <cstring> #include <algorithm> #include <vector> #include <queue> #include <stdlib.h> #include <string.h> #include<iomanip> #define N 500010 #define INF 10000000 #define LL long long #define eps 10E-9 #define mem(a) memset(a,0,sizeof(a)) #define w(a) while(a) #define s(a) scanf("%d",&a) #define ss(a,b) scanf("%d%d",&a,&b) #define sss(a,b,c) scanf("%lld%lld%lld",&a,&b,&c) #define MAXN 9999 #define MAXSIZE 10 #define DLEN 4 using namespace std; class BigNum { private:int a[500]; //能够控制大数的位数int len; //大数长度 public:BigNum(){ len = 1;memset(a,0,sizeof(a)); } //构造函数BigNum(const int); //将一个int类型的变量转化为大数BigNum(const char*); //将一个字符串类型的变量转化为大数BigNum(const BigNum &); //拷贝构造函数BigNum &operator=(const BigNum &); //重载赋值运算符。大数之间进行赋值运算friend istream& operator>>(istream&, BigNum&); //重载输入运算符friend ostream& operator<<(ostream&, BigNum&); //重载输出运算符BigNum operator+(const BigNum &) const; //重载加法运算符,两个大数之间的相加运算BigNum operator-(const BigNum &) const; //重载减法运算符,两个大数之间的相减运算BigNum operator*(const BigNum &) const; //重载乘法运算符,两个大数之间的相乘运算BigNum operator/(const int &) const; //重载除法运算符,大数对一个整数进行相除运算BigNum operator^(const int &) const; //大数的n次方运算int operator%(const int &) const; //大数对一个int类型的变量进行取模运算bool operator>(const BigNum & T)const; //大数和还有一个大数的大小比較bool operator>(const int & t)const; //大数和一个int类型的变量的大小比較void print(); //输出大数 }; BigNum::BigNum(const int b) //将一个int类型的变量转化为大数 { int c,d = b;len = 0;memset(a,0,sizeof(a));while(d > MAXN){ c = d - (d / (MAXN + 1)) * (MAXN + 1);d = d / (MAXN + 1);a[len++] = c;}a[len++] = d; } BigNum::BigNum(const char*s) //将一个字符串类型的变量转化为大数 { int t,k,index,l,i;memset(a,0,sizeof(a));l=strlen(s);len=l/DLEN;if(l%DLEN)len++;index=0;for(i=l-1;i>=0;i-=DLEN){ t=0;k=i-DLEN+1;if(k<0)k=0;for(int j=k;j<=i;j++)t=t*10+s[j]-'0';a[index++]=t;} } BigNum::BigNum(const BigNum & T) : len(T.len) //拷贝构造函数 { int i;memset(a,0,sizeof(a));for(i = 0 ; i < len ; i++)a[i] = T.a[i]; } BigNum & BigNum::operator=(const BigNum & n) //重载赋值运算符,大数之间进行赋值运算 { int i;len = n.len;memset(a,0,sizeof(a));for(i = 0 ; i < len ; i++)a[i] = n.a[i];return *this; } istream& operator>>(istream & in, BigNum & b) //重载输入运算符 { char ch[MAXSIZE*4];int i = -1;in>>ch;int l=strlen(ch);int count=0,sum=0;for(i=l-1;i>=0;){ sum = 0;int t=1;for(int j=0;j<4&&i>=0;j++,i--,t*=10){ sum+=(ch[i]-'0')*t;}b.a[count]=sum;count++;}b.len =count++;return in; } ostream& operator<<(ostream& out, BigNum& b) //重载输出运算符 { int i;cout << b.a[b.len - 1];for(i = b.len - 2 ; i >= 0 ; i--){ cout.width(DLEN);cout.fill('0');cout << b.a[i];}return out; } BigNum BigNum::operator+(const BigNum & T) const //两个大数之间的相加运算 { BigNum t(*this);int i,big; //位数big = T.len > len ?
T.len : len;
for(i = 0 ; i < big ; i++){ t.a[i] +=T.a[i];if(t.a[i] > MAXN){ t.a[i + 1]++;t.a[i] -=MAXN+1;}}if(t.a[big] != 0)t.len = big + 1;elset.len = big;return t; } BigNum BigNum::operator-(const BigNum & T) const //两个大数之间的相减运算 { int i,j,big;bool flag;BigNum t1,t2;if(*this>T){ t1=*this;t2=T;flag=0;}else{ t1=T;t2=*this;flag=1;}big=t1.len;for(i = 0 ; i < big ; i++){ if(t1.a[i] < t2.a[i]){ j = i + 1;while(t1.a[j] == 0)j++;t1.a[j--]--;while(j > i)t1.a[j--] += MAXN;t1.a[i] += MAXN + 1 - t2.a[i];}elset1.a[i] -= t2.a[i];}t1.len = big;while(t1.a[len - 1] == 0 && t1.len > 1){ t1.len--;big--;}if(flag)t1.a[big-1]=0-t1.a[big-1];return t1; } BigNum BigNum::operator*(const BigNum & T) const //两个大数之间的相乘运算 { BigNum ret;int i,j,up;int temp,temp1;for(i = 0 ; i < len ; i++){ up = 0;for(j = 0 ; j < T.len ; j++){ temp = a[i] * T.a[j] + ret.a[i + j] + up;if(temp > MAXN){ temp1 = temp - temp / (MAXN + 1) * (MAXN + 1);up = temp / (MAXN + 1);ret.a[i + j] = temp1;}else{ up = 0;ret.a[i + j] = temp;}}if(up != 0)ret.a[i + j] = up;}ret.len = i + j;while(ret.a[ret.len - 1] == 0 && ret.len > 1)ret.len--;return ret; } BigNum BigNum::operator/(const int & b) const //大数对一个整数进行相除运算 { BigNum ret;int i,down = 0;for(i = len - 1 ; i >= 0 ; i--){ ret.a[i] = (a[i] + down * (MAXN + 1)) / b;down = a[i] + down * (MAXN + 1) - ret.a[i] * b;}ret.len = len;while(ret.a[ret.len - 1] == 0 && ret.len > 1)ret.len--;return ret; } int BigNum::operator %(const int & b) const //大数对一个int类型的变量进行取模运算 { int i,d=0;for (i = len-1; i>=0; i--){ d = ((d * (MAXN+1))% b + a[i])% b;}return d; } BigNum BigNum::operator^(const int & n) const //大数的n次方运算 { BigNum t,ret(1);int i;if(n<0)exit(-1);if(n==0)return 1;if(n==1)return *this;int m=n;while(m>1){ t=*this;for( i=1;i<<1<=m;i<<=1){ t=t*t;}m-=i;ret=ret*t;if(m==1)ret=ret*(*this);}return ret; } bool BigNum::operator>(const BigNum & T) const //大数和还有一个大数的大小比較 { int ln;if(len > T.len)return true;else if(len == T.len){ ln = len - 1;while(a[ln] == T.a[ln] && ln >= 0)ln--;if(ln >= 0 && a[ln] > T.a[ln])return true;elsereturn false;}elsereturn false; } bool BigNum::operator >(const int & t) const //大数和一个int类型的变量的大小比較 { BigNum b(t);return *this>b; } void BigNum::print() //输出大数 { int i;cout << a[len - 1];for(i = len - 2 ; i >= 0 ; i--){ cout.width(DLEN);cout.fill('0');cout << a[i];}cout << endl; } int main() { int i,n;BigNum x[101]; //定义大数的对象数组x[0]=1;for(i=1;i<101;i++)x[i]=x[i-1]*(4*i-2)/(i+1);while(scanf("%d",&n)==1 && n!=-1){ x[n].print();} return 0; }